Electrical Engineering Video
Posted by: engineer eye Posted date: 6:40 AM / comment : 0 Electrical, Engineering/Science Laws
Posted by: engineer eye Posted date: 6:40 AM / comment : 0 Electrical, Engineering/Science Laws
Posted by: engineer eye Posted date: 8:22 PM / comment : 0 Engineering/Science Laws
Posted by: engineer eye Posted date: 8:22 PM / comment : 0 Engineering/Science Laws
Definition of the ampere: If two long, parallel wires 1 m apart carry the same current and the force per unit length on each wire is 2x10-7N/m, then the current is defined to be 1 A. Consider two long, straight, parallel wires separated by a distance a and carrying currents I1 and I2 in the same direction. We can easily determine the force on one wire due to a magnetic field set up by the other wire. Wire 2, which carries a current I2, creates a magnetic field B2 at the position of wire 1. The direction of B2 is perpendicular to wire1. | |
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The magnitude force on a length l of wire 1 is | |
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Sincel is perpendicular to B2, the magnitude of F1 is | |
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We can rewrite this in terms of the force per unit length as | |
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The numerical value of 2x10-7 N/m is obtained from the equation above with I1= I2= 1 A and a = 1 m. The Ampère's law states that the line integral of B.ds around any closed path equals ![]() | |
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Ampère's law is valid only for steady currents and is useful only for calculating the magnetic field of current configurations having a high degree of symmetry. |
Posted by: engineer eye Posted date: 8:21 PM / comment : 0 Engineering/Science Laws
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Kepler's analysis first showed that the concept of circular orbits about the Sun had to be abandoned. He eventually discovered that the orbit of Mars could be accurately described by an ellipse with the Sun at one focal point. He then generalized this analysis to include the motion of all planets. The complete analysis is summarized in three statements, known as Kepler's laws: |
1. | All planets move in elliptical orbits with the Sun at one of the focal points. |
2. | The radius vector drawn from the Sun to a planet sweeps out equal areas in equal time intervals. |
3. | The square of the orbital period of any planet is proportional to the cube of the semimajor axis of the elliptical orbit. |
Half century later, Newton demonstrated that these laws are the consequence of a simple force that exists between any two masses. Newton's law of gravity, together with his development of the laws of motion, provides the basis for a full mathematical solution to the motion of planets and satellites. More important, Newton's law of gravity correctly describes the gravitational attractive force between any two masses. |
Mathematical statements: | |
Kepler's second law | |
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Where dA is the area swept by radius vector r in a time dt and Mp is the planet mass. | |
Kepler's third law | |
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Where KS is a constant given by | |
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MS is the Sun mass, G is universal gravitational constant and T is the time. |
Posted by: engineer eye Posted date: 8:21 PM / comment : 0 Engineering/Science Laws
The law of atmospheres, also known as the barometric law, states that the pressure n(y) as a function of height y varies as: | |
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According to the ideal gas law, a gas of N particles in the thermal equilibrium obeys the relationship PV = NkBT. It is convenient to rewrite this equation in terms of the number of particles per unit volume of gas, nV = N/V. This quantity is important because it can vary from one point to another. In fact, our goal is to determine how nVchanges in our atmosphere. We can express the ideal gas law in terms of nV as P = nVkBT. Thus, if the number density nV is known, we can find the pressure and vice versa. | |
The pressure in the atmosphere decreases as the altitude increases because a given layer of air has to support the weight of the air above it — the greater the altitude, the less the weight of the air above that layer and the lower the pressure. | |
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To determine the variation in pressure with altitude, consider an atmospheric layer of thickness dy and the cross-sectional area A. Because the air is in static equilibrium, the upward force on the bottom of this layer, PA, must exceed the downward force on the top of the layer, (P + dP)A, by an amount equal to the weight of gas in this thin layer. If the mass of gas molecule in the layer is m, and the area a total of N molecules in the layer, then the weight of the layer is w = mgN = mgnVAdy. Thus A - (P + dP)A = mgnVAdy, Which reduces to dP = - mgnVdyBecause P = nVkBT, and T is assumed to remain constant, therefore dP = nVkBT dnV. | |
Substituting this into the above expression for dP and rearranging gives | |
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Integrating this expression, we find | |
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Boltzmann distribution law | |
Boltzmann distribution law is important in describing the statistical mechanics of a large number of particles. It states that the probability of finding the particles in a particular energy state varies exponentially as the negative of the energy divided by kBT. All the particles would fall into the lowest energy level, except that the thermal energy kBT tends to excite the particles to higher energy levels. | |
Distribution of particles in space is | |
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Where n0 is the number of particles where U = 0 This king of distribution applies to any energy the particles have, such as kinetic energy. In general, the relative number of particles having energy E is | |
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